2.07x^2-3.79x+1.34=0

Solution for 2.07x^2-3.79x+1.34=0 equation:

2.07x^2-3.79x+1.34=0

a = 2.07; b = -3.79; c = +1.34;
Δ = b2-4ac
Δ = -3.792-4·2.07·1.34
Δ = 3.2689
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3.79)-\sqrt{3.2689}}{2*2.07}=\frac{3.79-\sqrt{3.2689}}{4.14}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3.79)+\sqrt{3.2689}}{2*2.07}=\frac{3.79+\sqrt{3.2689}}{4.14}
$